Xavier Munford Net Worth 2018: What is this basketball player worth?

Xavier Munford is a professional basketball player who plays Point guard for the Milwaukee Bucks as number 0. Munford was born on June 1, 1992, in Hillside, New Jersey. Munford’s height is 6 ft 3 in. Munford’s weight is 173 pounds. This article takes a deep dive into Xavier Munford’s net worth.

Xavier Munford Career and Earnings/Salary

In high school, Xavier Munford played basketball for Saint Benedict’s Preparatory School (Newark, New Jersey). Munford played basketball in college with, Miami Dade College (2010-2011), Iowa Western Community College (2011-2012), and Rhode Island Rams men’s basketball (2012-2014) and started playing professionally in 2014. Munford was first drafted in 2014.

Munford played for the Northern Arizona Suns during 2014-2016 as well as the Memphis Grizzlies in 2015. Later, Munford played for the Greensboro Swarm throughout 2016-2017, the FC Barcelona Bàsquet over 2017, the Wisconsin Herd during 2017-2018, and the Milwaukee Bucks during 2017-present. Some of the highlights of Xavier Munford’s career include: NBA Development League All-Star Game.

Munford won a gold medal in the 2017 FIBA Americas Championship.

Xavier Munford Net Worth 2018

Basketball player salaries can range between $20,000 and tens of millions of dollars per annum, depending on a number of statistics. Although on average, NBA players earn a salary of approximately $2 million, a small contingent of players with D-league crossover contracts earn as little as $50,000. The salary cap for NBA players is around $100 million, although as of today no player brings in anywhere near that much money. The top players in the NBA earn nearly $35 million. Outside of the NBA, yearly earnings can dip below $20,000 annually for minor league teams.