Shannon Sharpe Net Worth 2018: What is this NFL football player worth?

Shannon Sharpe is a professional football player who plays Tight end as number 81, 84, 82. Sharpe’s height is 6 ft 2 in. Sharpe was born on June 26, 1968, in Chicago, Illinois. This page looks closely at Shannon Sharpe’s net worth.

Shannon Sharpe Net Worth 2018: What is this NFL football player worth?Image Credit: Staff Sgt Kristi Machado, USAF

Shannon Sharpe Career and Earnings/Salary

In high school, Shannon Sharpe played football for Glennville High School. Sharpe played college football on the Savannah State Tigers football team. In the 1990 NFL draft, Sharpe was chosen number 192 in round 7.

In the past, Sharpe played for the Denver Broncos, Baltimore Ravens, and Denver Broncos. Some of the highlights of Shannon Sharpe’s career include: 3× Super Bowl champion, 8× Pro Bowl, 4× First-team All-Pro, Second-team All-Pro, and NFL 1990s All-Decade Team, Denver Broncos, Savannah State Tigers football retired.

Some of Sharpe’s most prominent statistics include 62 Touchdowns, 10,060 Receiving yards, and 815 Reception (American football).

Shannon Sharpe Net Worth 2018

Football player salaries range heavily. At the starting level, NFL players earn between $400,000 and $600,000 per year. At the top end, players can make $50 million or more. The National Football League salary cap is approximately $175 million.

Shannon Sharpe net worth
Shannon Sharpe net worth: football salary distribution

So what is NFL football player Shannon Sharpe’s net worth in 2018? Our estimate for Shannon Sharpe’s net worth as of 2018 is: $14 million

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