Rob Gronkowski Net Worth 2018: What is this NFL football player worth?

Rob Gronkowski is a professional football player who plays Tight end for the New England Patriots as number 87. Gronkowski’s height is 6 ft 6 in. Gronkowski was born on May 14, 1989, in Amherst, New York. This page looks closely at Rob Gronkowski’s net worth.

Image Credit: Jeffrey Beall

Rob Gronkowski Career and Earnings/Salary

In high school, Rob Gronkowski played football for Woodland Hills High School. Gronkowski played college football on the Arizona Wildcats football team. In the 2010 NFL draft, Gronkowski was chosen number 42 in round 2.

In the past, Gronkowski played for the New England Patriots. Some of the highlights of Rob Gronkowski’s career include: 2× Super Bowl champion, 5× Pro Bowl, 5× First-team All-Pro, NFL Comeback Player of the Year, and List of National Football League season receiving touchdowns leaders.

Some of Gronkowski’s most prominent statistics include 76 Receiving touchdowns, 7,179 Receiving yards, and 474 Receptions.

Rob Gronkowski Net Worth 2018

In 2018, Rob Gronkowski is under contract to earn a salary of $11 million. Gronkowski’s contract extends until 2019, with a total compensation of $12 million in 2019. NFL player salaries range significantly. At the starting level, NFL players earn $400,000-$600,000 a year. At the top level, stars can bring in $50 million plus. The NFL salary cap is around $170 million.


Rob Gronkowski net worth: football salary distribution

So what is NFL football player Rob Gronkowski’s net worth in 2018? Our estimate for Rob Gronkowski’s net worth as of 2018 is: $12 million

Looking for other NFL football players? Check out these net worth articles: Tony Beckham, Jeff Knox Jr., Larry Willingham, Darrell Reid, Tom Zbikowski, Reggie Kelly, Jahwan Edwards, Dashon Goldson, Lauvale Sape, Ray Terrell, and Steve Nemeth.