Paul Seymour Net Worth 2018: What is this NFL football player worth?
Paul Seymour is a professional football player who plays Tight end as number 87. Seymour was born on February 6, 1950, in Detroit, Michigan. Seymour’s height is 6 ft 7 in. This page looks closely at Paul Seymour’s net worth.
Paul Seymour Career and Earnings/Salary
In high school, Paul Seymour played football for Shrine Catholic High School. Seymour played college football on the Michigan Wolverines football team. In the 1973 NFL draft, Seymour was chosen number 7 in round 1.
In the past, Seymour played for the Buffalo Bills. Some of the highlights of Paul Seymour’s career include: Consensus first-team All-American.
Paul Seymour Net Worth 2018
NFL salaries range significantly. At the bottom, NFL players make between $400,000 and $600,000 annually. At the top level, stars can bring in $50 million or more. The National Football League salary cap is nearly $170 million.
Paul Seymour net worth: football salary distribution
So what is NFL football player Paul Seymour’s net worth in 2018? Our estimate for Paul Seymour’s net worth as of 2018 is:
Looking for other NFL football players? Check out these net worth articles: Bob Picard, Tony Norman, Ron Botchan, Hugo Hollas, Drew Pearson, Gabe Wilkins, Kevin Turner, Ken Campbell, Melvin Tuten, Ricky Watters, and Lance Smith.
