O. J. Howard is a professional football player who plays Tight end for the Tampa Bay Buccaneers as number 80. Howard was born on November 19, 1994, in Prattville, Alabama. Howard’s height is 6 ft 6 in. This page looks closely at O. J. Howard’s net worth.
In high school, O. J. Howard played football for Autauga Academy. Howard played college football on the Alabama Crimson Tide football team. In the 2017 NFL draft, Howard was chosen number 19 in round 1.
In the past, Howard played for the Tampa Bay Buccaneers. Some of the highlights of O. J. Howard’s career include: College Football Playoff National Championship, and SEC Championship Game.
Some of Howard’s most prominent statistics include 6 Receiving touchdowns, 432 Receiving yards, and 26 Receptions.
Football player salaries range greatly. At the lowest level, NFL players make between $400,000 and $600,000 a year. At the highest, stars can make $50 million plus. The NFL salary cap is around $175 million.
So what is NFL football player O. J. Howard’s net worth in 2018? Our estimate for O. J. Howard’s net worth as of 2018 is:
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