O. J. Howard Net Worth 2018: What is this NFL football player worth?

O. J. Howard is a professional football player who plays Tight end for the Tampa Bay Buccaneers as number 80. Howard was born on November 19, 1994, in Prattville, Alabama. Howard’s height is 6 ft 6 in. This page looks closely at O. J. Howard’s net worth.

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O. J. Howard Career and Earnings/Salary

In high school, O. J. Howard played football for Autauga Academy. Howard played college football on the Alabama Crimson Tide football team. In the 2017 NFL draft, Howard was chosen number 19 in round 1.

In the past, Howard played for the Tampa Bay Buccaneers. Some of the highlights of O. J. Howard’s career include: College Football Playoff National Championship, and SEC Championship Game.

Some of Howard’s most prominent statistics include 6 Receiving touchdowns, 432 Receiving yards, and 26 Receptions.

O. J. Howard Net Worth 2018

Football player salaries range greatly. At the lowest level, NFL players make between $400,000 and $600,000 a year. At the highest, stars can make $50 million plus. The NFL salary cap is around $175 million.

O. J. Howard net worth
O. J. Howard net worth: football salary distribution

So what is NFL football player O. J. Howard’s net worth in 2018? Our estimate for O. J. Howard’s net worth as of 2018 is:

Looking for other NFL football players? Check out these net worth articles: Ross Brupbacher, Houston Bates, J Torchio, James Thrash, Howard Ballard, Larry Brahm, Niko Koutouvides, Ron Morris, Rod Streater, R. B. Nunnery, and Bookie Bolin.