Lee Mazzilli is a pro baseball player who plays Center fielder / First baseman. Mazzilli was born on March 25, 1955, in Brooklyn, New York. This page will take a closer look at Lee Mazzilli’s net worth.
Mazzilli bats Switch and throws Right. Mazzilli debuted in the MLB on September 7, 1976 for the New York Mets. In all, Mazzilli played for the New York Mets, Texas Rangers, New York Yankees, Pittsburgh Pirates, New York Mets, Toronto Blue Jays, Baltimore Orioles, and New York Yankees. Mazzilli’s career ended with the Toronto Blue Jays in 1989.
Some of Mazzilli’s most prominent statistics in the MLB included a Batting average stat of .259, a Home runs stat of 93, and a Runs batted in stat of 460. Some of the highlights of Lee Mazzilli’s career include: Major League Baseball All-Star Game, and 2× World Series champion.
Lee Mazzilli was last under contract in 1989, according to USA Today, with a 1 (1989) year package worth $400,000. Over the years, Mazzilli earned $400,000 in 1988, and $400,000 in 1989.
Baseball player annual pay can range widely. In Major League Baseball, the median pay is about $3 million annually. Top MLB players can make $25 million or more per annum, and lower rated players earn $1 million or less.
Outside the MLB, most contracts pay less than $10,000 a year.
So what is baseball player Lee Mazzilli’s net worth in 2018? Our estimate for Lee Mazzilli’s net worth as of 2018 is: $700,000
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