A. J. English was a professional basketball player who played Shooting guard as number 14. English’s height is 6 ft 3 in. English’s weight is 175 pounds. English was born on July 11, 1967, in Wilmington, Delaware. This article takes a deep dive into A. J. English’s net worth.
In high school, A. J. English played basketball for Howard High School of Technology; (Wilmingon, Delaware). English played basketball in college with Men’s basketball (1986-1990) and started playing professionally in 1990. In the 1990 draft, English was chosen number 37 in round 2 by the Washington Wizards. English left the game of basketball in 2000.
English played for the Washington Wizards during 1990-1991 as well as the Pallacanestro Trieste in 1992-1993. Later, English played for the Rapid City Thrillers throughout 1993, the Rochester Renegade over 1993-1994, the Pallacanestro Virtus Roma during 1994, and the Libertas Pallacanestro Forlì during 1994. Some of the highlights of A. J. English’s career included: State Farm Division II Player of the Year.
English set a career record of 1,502 (9.9 ppg) points, 315 (2.1 rpg) rebounds, and 320 (2.1 apg) assists.
Basketball annual payments can range between a few thousand dollars and millions of dollars per annum, depending on a number of factors. Although most professional NBA players make a salary of approximately $2 million, a few with D-league crossover contracts earn as little as $50,000. The salary cap for NBA players is close to $100 million, although as of today no player makes anywhere near that much money. The top players earn around $35 million. Outside of the NBA, yearly earnings can go below $20,000 per year for minor league teams.
So what is basketball player A. J. English’s net worth in 2018? Our estimate for A. J. English’s net worth as of 2018 is:
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