A. J. English Net Worth 2018: What is this basketball player worth?

A. J. English was a professional basketball player who played Shooting guard as number 14. English’s height is 6 ft 3 in. English’s weight is 175 pounds. English was born on July 11, 1967, in Wilmington, Delaware. This article takes a deep dive into A. J. English’s net worth.

A. J. English Career and Earnings/Salary

In high school, A. J. English played basketball for Howard High School of Technology; (Wilmingon, Delaware). English played basketball in college with Men’s basketball (1986-1990) and started playing professionally in 1990. In the 1990 draft, English was chosen number 37 in round 2 by the Washington Wizards. English left the game of basketball in 2000.

English played for the Washington Wizards during 1990-1991 as well as the Pallacanestro Trieste in 1992-1993. Later, English played for the Rapid City Thrillers throughout 1993, the Rochester Renegade over 1993-1994, the Pallacanestro Virtus Roma during 1994, and the Libertas Pallacanestro Forlì during 1994. Some of the highlights of A. J. English’s career included: State Farm Division II Player of the Year.

English set a career record of 1,502 (9.9 ppg) points, 315 (2.1 rpg) rebounds, and 320 (2.1 apg) assists.

A. J. English Net Worth 2018

Basketball annual payments can range between a few thousand dollars and millions of dollars per annum, depending on a number of factors. Although most professional NBA players make a salary of approximately $2 million, a few with D-league crossover contracts earn as little as $50,000. The salary cap for NBA players is close to $100 million, although as of today no player makes anywhere near that much money. The top players earn around $35 million. Outside of the NBA, yearly earnings can go below $20,000 per year for minor league teams.