Collin Sexton Net Worth 2018: What is this basketball player worth?
Collin Sexton is a professional basketball player who plays Point guard for the Alabama Crimson Tide as number 2. Sexton was born on January 4, 1999, in Marietta, Georgia. Sexton’s height is 6 ft 3 in. This article takes a deep dive into Collin Sexton’s net worth.
Collin Sexton Career and Earnings/Salary
In high school, Collin Sexton played basketball for Pebblebrook High School (Mableton, Georgia). Sexton played basketball in college with Alabama Crimson Tide men’s basketball (2017-present).
Some of the highlights of Collin Sexton’s career include: McDonald’s All-American Game, McDonald’s All-American Game Slam Dunk Contest champion, Jordan Brand Classic, and FIBA Under-17 World Championship MVP.
Collin Sexton Net Worth 2018
Player yearly earnings range between a few thousand dollars and millions of dollars annually, depending on a number of considerations. Although on average, NBA players earn a salary of around $2 million, a few with D-league crossover contracts earn as little as $50,000. The salary cap for NBA players is around $100 million, although as of today no player brings in anywhere near that much money. The top players earn approximately $35 million. Outside of the NBA, annual payments can be as low as $20,000 annually for minor league teams.
Collin Sexton net worth: basketball salary distribution
So what is basketball player Collin Sexton’s net worth in 2018? Our estimate for Collin Sexton’s net worth as of 2018 is:
Looking for other basketball players? Check out these basketball net worth articles: Sandrine Gruda, Ružica Meglaj-Rimac, Mohamed Youssef, Sidney Lowe, Darrel Brown, Wiley Peck, Gilbert Brown, Jean-Marc Mwema, Wade Baldwin IV, María Pina, and Mohammed Yousuf.
