Bob Henley is a pro baseball player who plays Catcher / coach for the Washington Nationals as # 13. Henley was born on January 30, 1973, in Mobile, Alabama. This page will take a closer look at Bob Henley’s net worth.
Henley bats Right and throws Right. Henley debuted in the MLB on July 19, 1998 for the Montreal Expos. In all, Henley played for the Montreal Expos. Henley’s career ended with the Montreal Expos in 1998.
Some of Henley’s most prominent statistics in the MLB included a Batting average stat of .304, a Home runs stat of 3, and a Runs batted in stat of 18.
Bob Henley was last under contract in 2000, according to USA Today, with a 1 (2000) year package worth $200,000. Over the years, Henley earned $200,000 in 1998, $200,000 in 1999, and $200,000 in 2000.
Baseball player compensation can range widely. In professional baseball, the average player earns about $3 million every year. Top pro baseball players can make $25 million or more every year, and lower paid players bring in $1 million or less.
In the minor leagues, most contracts are worth less than $10,000 a year.
So what is baseball player Bob Henley’s net worth in 2018? Our estimate for Bob Henley’s net worth as of 2018 is: $700,000
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