Arnie Ferrin Net Worth 2018: What is this basketball player worth?

Arnie Ferrin was a professional basketball player. Ferrin’s weight is 180 pounds. Ferrin’s height is 6 ft 2 in. Ferrin was born on July 29, 1925, in Salt Lake City, Utah. This article takes a deep dive into Arnie Ferrin’s net worth.

Arnie Ferrin Career and Earnings/Salary

In high school, Arnie Ferrin played basketball for Ogden High School (Ogden, Utah) (Ogden, Utah). Ferrin played basketball in college with Utah Utes men’s basketball (1943-1948) and started playing professionally in 1948. In the 1948 draft, Ferrin was chosen number — in round — by the Minneapolis Lakers. Ferrin left the game of basketball in 1951.

Ferrin played for the Minneapolis Lakers during 1948-49 BAA season 1950. Some of the highlights of Arnie Ferrin’s career included: 2× NBA champion, List of NCAA Men’s Division I Basketball champions, NCAA Basketball Tournament Most Outstanding Player, Consensus first-team NCAA Men’s Basketball All-Americans, 3× Consensus second-team All-American, and No. 22 Retired numbers.

Ferrin set a career record of 1,037 (5.8 ppg) points, 271 (4.0 rpg) rebounds, and 202 (1.6 apg) assists.

Arnie Ferrin Net Worth 2018

Basketball player yearly earnings can range between $20,000 and tens of millions of dollars per annum, depending on a number of statistics. Although most professional NBA players earn a salary of nearly $2 million, some with D-league crossover contracts receive as little as $50,000. The salary cap for National Basketball Association players is nearly $100 million, although as of today nobody makes anywhere near that much money. The top players earn around $35 million. Outside of the National Basketball Association, yearly earnings can be as low as $20,000 per year for minor league teams.