Armonty Bryant Net Worth 2018: What is this NFL football player worth?
Armonty Bryant is a professional football player who plays Defensive end for the Free agent. Bryant’s height is 6 ft 4 in. Bryant was born on May 20, 1990, in Wichita Falls, Texas. This page looks closely at Armonty Bryant’s net worth.
Image Credit: Erik Drost
Armonty Bryant Career and Earnings/Salary
In high school, Armonty Bryant played football for Wichita Falls High School. Bryant played college football on the East Central Tigers football team. In the 2013 NFL draft, Bryant was chosen number 217 in round 7.
In the past, Bryant played for the Cleveland Browns, and Detroit Lions.
Some of Bryant’s most prominent statistics include 3 Forced fumbles, 11.5 Quarterback sacks, and 68 Total tackles.
Armonty Bryant Net Worth 2018
In 2018, Armonty Bryant is under contract to earn a salary of $600,000. NFL player salaries range greatly. At the lowest level, NFL rookies make as much as $400,000 to $600,000 per year. At the top level, NFL players can make $50 million plus. The NFL salary cap is around $170 million.
Armonty Bryant net worth: football salary distribution
So what is NFL football player Armonty Bryant’s net worth in 2018? Our estimate for Armonty Bryant’s net worth as of 2018 is:
Looking for other NFL football players? Check out these net worth articles: Jay Bachman, Condrew Allen, Jeff Otis, Jason Banks, Brian Smith, Don Herndon, Dom Principe, Greg Mancz, Russ Peterson, Dee Martin, and Jim Brumfield.
