Alex Stepanovich Net Worth 2018: What is this NFL football player worth?
Alex Stepanovich is a professional football player who plays Center (American football) as number 71, 69. Stepanovich was born on September 25, 1981, in Berea, Ohio. Stepanovich’s height is 6 ft 4 in. This page looks closely at Alex Stepanovich’s net worth.
Alex Stepanovich Career and Earnings/Salary
In high school, Alex Stepanovich played football for Berea High School. Stepanovich played college football on the Ohio State Buckeyes football team. In the 2004 NFL draft, Stepanovich was chosen number 100 in round 4.
In the past, Stepanovich played for the Arizona Cardinals, Cincinnati Bengals, Atlanta Falcons, and Pittsburgh Steelers.
Some of Stepanovich’s most prominent statistics include 0 Fumble recoveries, 46 Games played, and 34 Games started.
Alex Stepanovich Net Worth 2018
NFL player salaries range significantly. At the starting level, NFL players earn as much as $400,000 to $600,000 a year. At the top level, players can bring in $50 million plus. The NFL salary cap is nearly $175 million.
Alex Stepanovich net worth: football salary distribution
So what is NFL football player Alex Stepanovich’s net worth in 2018? Our estimate for Alex Stepanovich’s net worth as of 2018 is:
Looking for other NFL football players? Check out these net worth articles: Ken Norton Jr., Tom Smith, Rick Lackman, Quentin Saulsberry, Jim Leo, Jamie Stoddard, George Rosso, Jeremy Navarre, Rodney Wallace, Rod Marinelli, and Jared Green.
