Al Jefferson Net Worth 2018: What is this basketball player worth?

Al Jefferson is a professional basketball player who plays Center for the Indiana Pacers as number 25. Jefferson’s height is 6 ft 10 in. Jefferson’s weight is 289 pounds. Jefferson was born on January 4, 1985, in Monticello, Mississippi. This article takes a deep dive into Al Jefferson’s net worth.

Image Credit: Keith Allison

Al Jefferson Career and Earnings/Salary

In high school, Al Jefferson played basketball for Prentiss High School (Prentiss, Mississippi). Jefferson started playing professionally in 2004. In the 2004 National Basketball Association draft, Jefferson was chosen number 15 in round 1 by the Boston Celtics.

Jefferson played for the Boston Celtics during 2004-2006 as well as the Minnesota Timberwolves in 2007-2009. Later, Jefferson played for the Utah Jazz throughout 2010-2012, the Charlotte Hornets over 2013-2015, and the Indiana Pacers during 2016-present. Some of the highlights of Al Jefferson’s career include: All-NBA Third Team, NBA All-Rookie Second Team, First-team Parade All-America Boys Basketball Team, and McDonald’s All-American Game.

Al Jefferson Net Worth 2018

Basketball salaries vary between $20,000 and tens of millions of dollars per annum, depending on a number of considerations. Although typical NBA players earn a salary of around $2 million, some with D-league crossover contracts earn as little as $50,000. The salary cap for National Basketball Association players is nearly $100 million, although currently no player earns anywhere near that amount. The top players in the NBA earn approximately $35 million. Outside of the NBA, salaries can dip below $20,000 annually for minor league teams.