Abram Elam is a professional football player who plays Safety (American football position) as number 37, 27, 26, 24, 32. Elam was born on October 15, 1981, in West Palm Beach, Florida. Elam’s height is 6 ft 0 in. This page looks closely at Abram Elam’s net worth.
In high school, Abram Elam played football for Cardinal Newman High School (West Palm Beach, Florida). Elam played college football on the Kent State Golden Flashes football team.
In the past, Elam played for the Dallas Cowboys, New York Jets, Cleveland Browns, Dallas Cowboys, and Kansas City Chiefs. Some of the highlights of Abram Elam’s career include: New York Jets.
Some of Elam’s most prominent statistics include 3 Interceptions, 5.0 Quarterback sacks, 408 Tackle (football move)s, and 104 Games played.
NFL salaries range dramatically. At the low end, NFL players earn as much as $400,000 to $600,000 a year. At the highest level, stars can make $50 million plus. The National Football League salary cap is around $170 million.
So what is NFL football player Abram Elam’s net worth in 2018? Our estimate for Abram Elam’s net worth as of 2018 is:
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