A. J. Jefferson Net Worth 2018: What is this NFL football player worth?
A. J. Jefferson is a professional football player who plays Cornerback for the Edmonton Eskimos as number 72. Jefferson’s height is 6 ft 1 in. Jefferson was born on April 4, 1988, in Bakersfield, California. This page looks closely at A. J. Jefferson’s net worth.
Image Credit: Jeffrey Beall
A. J. Jefferson Career and Earnings/Salary
In high school, A. J. Jefferson played football for West High School (Bakersfield, California). Jefferson played college football on the Fresno State Bulldogs football team.
In the past, Jefferson played for the Arizona Cardinals, Minnesota Vikings, Seattle Seahawks, Toronto Argonauts, Ottawa Redblacks, Saskatchewan Roughriders, and Edmonton Eskimos.
Some of Jefferson’s most prominent statistics include 2 Interceptions, 109 Tackle (football move), and 0 Quarterback sack.
A. J. Jefferson Net Worth 2018
NFL player salaries range significantly. At the lowest level, NFL players make $400,000-$600,000 per year. At the highest, NFL players can earn $50 million or more. The National Football League salary cap is approximately $170 million.
A. J. Jefferson net worth: football salary distribution
So what is NFL football player A. J. Jefferson’s net worth in 2018? Our estimate for A. J. Jefferson’s net worth as of 2018 is:
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