• Brooke Austin Net Worth 2018: What is this tennis player worth?


    Brooke Austin is a tennis player who was born on February 12, 1996, in Indianapolis, United States, and is a total of 2 m tall. This article will take a look at Brooke Austin’s net worth.

    Brooke Austin Net Worth 2018: What is this tennis player worth?Image Credit: Flickr: si.robi

    Brooke Austin Career, Earnings

    Austin lives in Indianapolis, United States, plays Right-handed (two handed-backhand) and attended University of Florida (2014-current).

    Over an accomplished career, Austin won a total of 1 ITF singles titles, won a total of 2 ITF doubles titles and earned a total of $32,036 from competition. Austin has won 1 ITF singles titles, with a record of 69-52 and reached a rank of No. 424 (26 August 2013). Austin has won 2 ITF doubles titles, with a record of 20-15 and reached a rank of No. 638 (27 May 2013) in doubles play.

    Brooke Austin has a US Open junior record of Q2 (2012 US Open (tennis)).

    Brooke Austin competed in doubles events with good results, including a US Open Doubles record that includes achieving a number one ranking (2016 US Open (tennis)).

    Brooke Austin Net Worth 2018

    So what is Brooke Austin’s net worth in 2018? Austin earned a total of $32,036 from competition according to Wikipedia, but that’s not all of Austin’s earnings, which may include sponsorships, businesses, and promotions. Our estimate for Brooke Austin’s net worth in 2018 is:

    Looking for other related tennis players? Check out the net worth numbers for Agnė Čepelytė, David Felgate, Patrick Galbraith, Natsumi Hamamura, Lee So-ra, Miki Miyamura, David Rice, Andrei Stoliarov, Pablo Santos Gonzalez, Miriam Oremans, and Brian Teacher.

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